Consider
3^{2 }= 3 + 3 + 3 ( Three added three times. )
5^{2} = 5+5+5+5+5 ( Five added five times. )
X^{2} = x+x+x+x+ …… x times
Find first derivative w.r.t. x on both sides.
2x = 1+1+1+1+…… x times
2x = x cancelling x on both side

Find the error!
Contact Vissicomp : 26708190 / 7506909158
Edited by Dr. Ashwin I Mehta
]]>Let us assume that a store is selling only three items namely ‘bread’,’butter’ and ‘jam’. A customer can purchase all three items i.e. [‘bread’,’butter’,’jam’], a list in Python . He can also buy any combinations of them. Therefore I need to find all subsets of above set. A program to find subset is given here.
#recursion in arrays
def subs(l):
if l == []:
return [[]]
x=subs(l[1:])
return x+[[l[0]]+y for y in x]
The function subs() defined above will generate power set of set [‘bread’,’butter’,’jam’]. In a screen shot given below program and its output both are shown.
Output shows all possible subsets of a universal set . For further analysis and finding “large item set “ I will label these sets as l1, l2 l3…… and so on. Therefore , let
l1=[‘bread’], l2= [‘butter’], l3=[‘jam’],l4=[‘bread’, ‘butter’], l5= [‘bread’,’jam’], l6= [‘jam’,’butter’], l7= [‘bread’,’butter’,’jam’]. We leave out an empty set. Let us say on a particular day we have following sales data:
daysale= [‘l1’,’l2’,’l3’, ‘l4’,’l7’,’l4’, ‘l5’,’l5’,’l6’,‘l4’,’l4’,’l5’,‘l7’,’l4’,’l6’]
Data shows we have 15 sale deal on that particular day. To determine large dataset , we need to determine frequency of each of l1,l2,l3,….. . This is done by following program.
Output shows ‘l4’ has occurred 5 times, ‘l5’ has occurred 3 times and so on . so if we set threshold as 3 only ‘l4’ and ‘l5’ will be candidate for large dataset.
I will welcome suggestions from all of you.
For Machine Learning join Vissicomp. Contact us at /9820681349.
Created and edited by Dr. Ashwin I Mehta at Vissicomp Technology.
]]>There is a 150 percent increase in the job postings for cyber security roles between January 2017 and March 2018, according to a survey by online job portal Indeed .
The data showed that Bengaluru accounts for the highest number (36 percent) of jobs in the sector in India.
Between January 2017 and March 2018, the survey said that there has also been a spike in the number of job postings for data protection roles, which have seen an increase of 143 percent. The number of job searches for the same have risen by 188 percent.
As per the survey, implementation of the General Data Protection Regulation (GDPR) law in Europe has stimulated Indian companies to fortify their databases, leading to an upswing in the search for cyber security and privacy professionals.
Further, Indeed said that the unprecedented increase in the number of cybercrimes in the country has also created a number of job opportunities for data protection and cyber security professionals. According to the Cybersecurity Jobs Report 20182021, cybercrime will more than triple the number of job openings over the next five years.
After Bengaluru, Mumbai (17 percent), NCR region (12 percent), Pune (9 percent) and Hyderabad (8 percent) are the other locations for work opportunities in the sector in India.
Sashi Kumar, Managing Director, Indeed India, said that companies across the world are gearing up to ensure compliance to General Data Protection Regulation (GDPR) and ePrivacy requirements.
“While the larger technology giants are more or less equipped to comply, it is the midsize and smaller firms that are seeking professionals to help them cope with the requirements the new laws entail,” he added.
Indeed’s data also highlights a high level of interest in the field among the age group of 2630 years. Interestingly, people between the age group of 4145 years also show high levels of interest in these profiles, as compared to those between 3135 years of age.
]]>Use the 4th order RungeKutta method with h = 0.1 to find the
approximate solution for y(1.1), working to 4 decimal places, for the
initial value problem:
dy/dx = 2xy, y(1) = 1
sol:
We have dy/dx = f(x,y) = 2xy.
If you require the 4th order approximation the formula will be:
y(x0 + h) = y(x0) + (1/6)[w1 + 2w2 + 2w3 + w4]
where:
w1 = h*f(x0.y0) = 0.1(2)(1)(1) = 0.2
w2 = h*f(x0 + h/2, y0 + w1/2) = 0.1(2)(1.05)(1.1) = 0.231
w3 = h*f(x0 + h/2, y0 + w2/2) = 0.1(2)(1.05)(1.1155) = 0.234255
w4 = h*f(x0 + h, y0 + w3) = 0.1(2)(1.1)(1.234255) = 0.2715361
and so:
y(1.1) = 1 + (1/6)[0.2 + 2(0.231) + 2(0.234255) + 0.2715361]
= 1.23367435
We can compare this with the exact solution to the problem.
dy/y = 2x dx
and integrating:
ln(y) = x^2 + C
and y = 1 when x = 1
0 = 1 + C
and so C = 1. Therefore:
ln(y) = x^2 – 1
y = e^(x^21)
When x = 1.1 this gives:
y = e^(1.1^2 1)
= e^0.21
= 1.23367806
which is same as RungeKutta up to the 5th decimal place.
Edited by : Dr. Ashwin I Mehta
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I have asked some of my students to look into the particular topic and shared the details of VISSICOMP TECHNOLOGY. I will be sending you the list of interested students as soon as they confirm.
Thank you for your cooperation and the opportunity.
Nikhil Shrivas
Assistant Professor
Department of Mechatronics Engineering
School of Automobile, Mechanical & Mechatronics Engineering (SAMM)
Manipal University Jaipur
]]>Thanks for your quick and positive response. I am happy to see your reply. It would be really great thing to connect the IndustryAcademia relationship and feel the gap between Industry and Academic. It will be really a very good platform for young minds. In near future, I will send some more students at your organization definitely and would be happy to invite you in our department for some guest lectures and collaborations to grow together.
Thank you once again for your support.
Looking forward for some kind of collaborations and IndustryAcademia relationship.
Thanks & Regards,
Prabhat Ranjan
Assistant Professor
Department of Mechatronics Engineering
School of Automobile, Mechanical & Mechatronics Engineering (SAMM)
Manipal University Jaipur
]]>
Mehta Sir  

Time 
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34:30pm  –  Hencita,GauravPython & Html  Hencita,GauravPython & Html  –  Hencita,GauravPython & Html 
4:306pm  Hencita,GauravPython & Html  –  –  Hencita,GauravPython & Html  – 
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(A) 23
(B) 24
(C) 48
(D) 56
(E) 81
Quantity A Quantity B
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